The performance curve of a pump is represented by the following function:
h=266.7-.6667q2
where h is head in feet, and q is discharge in cfs.
If three of these pumps were used in series, what would be the head at a discharge of 12.4 cfs?
Head and discharge relations
h= (266.7-0.6667*q^2) ( ie head will decrease as discharge increases)
when the pumps are in series,the discharge will remain constant and head will be additive of the 3 pumps.
for discharge, q = 12.4 cfs,
head,h = 266.7-0.6667*(12.4^2) = 164.19 feet
so total head at discharge 12.4 cfs when 3 pumps are in sereis = 3*164.19 = 492.56 feet (ans)
The performance curve of a pump is represented by the following function: h=266.7-.6667q2 where h is...
The performance curve of a pump is represented by the following function: h=266.7-.6667q2 where h is head in feet, and q is discharge in cfs. If three of these pumps were used in series, what would be the head at a discharge of 12.4 cfs?
I do not have the graph but can u give the best possible
solution that applies to a typical graph.
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Mechanical Lab II. Please answer asap with clear work. Thank
you!
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