Question

Write the oxidation numbers UNDER all the elements in the following oxidation-reduction reaction: 5NaBiO3(s) + 2...

Write the oxidation numbers UNDER all the elements in the following oxidation-reduction reaction: 5NaBiO3(s) + 2 MnCl2(aq) + 16HCl(aq)  5NaCl(aq) + 5BiCl3(aq) + 2HMnO4(aq)+7H2O(l) Identify the element being oxidized and reduced.

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The oxidation numbers of all the elments present in the reaction equation is mentioned in the picture below...

The element whose oxidation number has been decreased , is called as reduced , and the one whose oxidation number increases in the equation is said to be oxidised.

So here , Bi is getting reduced and Mn is getting oxidised.

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Write the oxidation numbers UNDER all the elements in the following oxidation-reduction reaction: 5NaBiO3(s) + 2...
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