Differential leveling between BMs AA, BB, CC, DD, and AA gives elevation differences (in meters) of -15.242, +32.068, +37.824, and -54.635, and distances in kmkm of 2.0, 3.0, 1.0, and 4.0, respectively. The elevation of AA is 634.597.
Part A
Compute the adjusted elevations of BMs BB, CC, and DD.
Express your answers in meters to six significant figures. Enter your answers separated by commas.
Hi,
Solution as follows:
Elevation of a Stations = Elevation of Previous station + elevation difference
Accordingly Given readings are reproduced in tabular form below. Their respected elevations are also calculated:
Station |
Elevation difference (meter) |
Distance (km) |
Elevation (meter) |
Remarks |
BMAA |
634.597 |
Given |
||
BMBB |
-15.242 |
2 |
619.355 |
634.597 - 15.242 |
BMCC |
32.068 |
3 |
651.423 |
619.355 + 32.068 |
BMDD |
37.824 |
1 |
689.247 |
651.423 + 37.824 |
BMAA |
-54.635 |
4 |
634.612 |
689.247 - 54.635 |
Sum |
0.015 |
10 |
Since this is a closed loop survey, sum of elevation differences must be zero. Any remainder is error or misclosure.
In level surveys, it is observed that the error in a reading is directly proportional to distance between stations. Accordingly we will calculate the correction for each elevation based on below formula:
Correction=-1×total error×distance between stationsTotal Distance
Accordingly results are furnished below:
Station |
Elevation |
Distance |
Correction |
Adjusted |
Adjusted |
BMAA |
634.597000 |
||||
BMBB |
-15.242 |
2 |
-0.003000 |
-15.245000 |
619.352000 |
BMCC |
32.068 |
3 |
-0.004500 |
32.063500 |
651.415500 |
BMDD |
37.824 |
1 |
-0.001500 |
37.822500 |
689.238000 |
BMAA |
-54.635 |
4 |
-0.006000 |
-54.641000 |
634.597000 |
Sum |
0.015 |
10 |
-0.015000 |
0.000000 |
Hence the answers are: 619.352000, 651.415500, 689.238000
Hope the solution provided above is clear. In case of any clarifications, please leave comment in comments section.
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Differential leveling between BMs AA, BB, CC, DD, and AA gives elevation differences (in meters) of...