1. Consider the following function for an AVL tree with n nodes.
void
_removeLeftmost(struct Node *cur) {
while(cur->left != 0)
{
cur = cur->left
}
free(cur);
}
What is the average case big-O complexity of _removeLeftmost()?
a. O(1)
b. O(log n)
c. O(n)
d. None of the above
2. Refer to _removeLeftmost() from Question 1. What is the worst case big-O complexity of _removeLeftmost() for a binary search tree (not necessarily an AVL tree) with n nodes?
a. O(1)
b. O(log n)
c. O(n)
d. None of the above
1. Consider the following function for an AVL tree with n nodes. void _removeLeftmost(struct Node *cur) {...
a. The INORDER traversal output of a binary tree is U,N,I,V,E,R,S,I,T,Y and the POSTORDER traversal output of the same tree is N,U,V,R,E,T,I,S,I,Y. Construct the tree and determine the output of the PREORDER traversal output. b. One main difference between a binary search tree (BST) and an AVL (Adelson-Velski and Landis) tree is that an AVL tree has a balance condition, that is, for every node in the AVL tree, the height of the left and right subtrees differ by at most 1....
The time-complexity of searching an AVL tree is in the worst case and in the average case. On), On) O(logot). O(log O ON), C(n) 0(), O(log) Question 16 2 pts The time-complexity of searching a binary search tree is in the worst case and in the average case (1), O(log) O(logn), O(log,n) On), On) 001), 001)
fill in the blank Binary Search Tree AVL Tree Red-Black Tree complexity O(log N), O(N) in the worst case O(log N) O(log N) Advantages - Increasing and decreasing order traversal is easy - Can be implemented - The complexity remains O(Log N) for a large number of input data. - Insertion and deletion operation is very efficient - The complexity remains O(Log N) for a large number of input data. Disadvantages - The complexity is O(N) in the worst case...
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Data structures c++ 1- What is the search time in an AVL tree with n nodes. Select one or more: a. O(2^n) b. O(height * log n) c. O(log n) d. O(height) e. O(log height) f. O(n) g. O(1) h. O(2^height)
PROMPT: Consider a binary tree (not necessarily a binary search tree) with node structure. QUESTION: Prove that findMax works by mathematical induction. struct Node int val; struct Node * left; struct Node* right; The following function findMax returns the largest value 'val in the tree; and returns -1 if the tree is empty. You may assume that all the values 'val' in the tree are nonnegative. struct Node * findMax(struct Node root) if (rootNULL) return -1; maxval = root->val; maxval...
Using C Please comment Part 1: BST Create a link based Binary Search tree composed of a Node and a Tree struct. You should have a header file, BST.h, with the following: o Node struct containing left, right, and parent pointers, in addition to holding an Data struct value Tree struct containing a pointer to the root of the tree A function declaration for a function that allocates a tree, and initializes the root to NULL o o o A...
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a. How can I show that any node of a binary search tree of n nodes can be made the root in at most n − 1 rotations? b. using a, how can I show that any binary search tree can be balanced with at most O(n log n) rotations (“balanced” here means that the lengths of any two paths from root to leaf differ by at most 1)?