Match the confidence level with the confidence interval for the population mean.
1. ?bar±2.575(?/√n)
2. ?bar±1.645(?/√n)
3. ?bar±1.282(?/√n)
A. 80% B. 90% C. 99%
solution:
1. ?bar±2.575(?/√n)
At 99% confidence level the z is,
= 1 - 99%
= 1 - 0.99 = 0.01
/2 = 0.005
Z/2 = 2.576
2. ?bar±1.645(?/√n)
At 90% confidence level
= 1 - 90%
= 1 - 0.90 =0.10
/2
= 0.05
Z/2
= Z0.05 = 1.645
3.
?bar±1.282(?/√n)
At 80% confidence level
= 1 - 80%
= 1 - 0.80 =0.20
/2
= 0.10
Z/2
= Z0.10 = 1.282
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