Question

(Java Programming) The following is an old word puzzle: “Name a common word, besides tremendous, stupendous, and horrendous, that ends in dous.” If you think about this for a while it will probably come to you. However, we can also solve this puzzle by reading a text file of English words and outputting the word if it contains “dous” at the end. The text file “words.txt” contains 87314 English words, including the word that completes the puzzle. This file is available online with the source code for the book. Write a program that reads each word from the text file and outputs only those containing “dous” at the end to solve the puzzle.

Words.txt : https://drive.google.com/file/d/1gxmbAlNBY4BgxC3b0kplIdoMkUyxrgcH/view?usp=sharing

Answer 1

The java code for solving the puzzle is as follows:

import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;

//This class will read words from text file and solve the puzzle which required the words which ends with dous
public class Puzzle {
    public static void  main(String args[]){
        // The name of the file to open.
        String fileName = "F:\\words.txt";

        // This will reference one line at a time
        String line = null;

        try {
            // FileReader reads text files in the default encoding.
            FileReader fileReader = new FileReader(fileName);

            // Always wrap FileReader in BufferedReader.
            BufferedReader bufferedReader = new BufferedReader(fileReader);
            int count =0;

            while((line = bufferedReader.readLine()) != null) {
                //first I check the string length  is greater than 4 as dous is of size 4
                if(line.length()>4){
                    //I check lastIndexOf dous is not -1 usaull the value will be -1 if dous is not present
                    // if it is present it will send the value which is starting position of dous
                    if(line.lastIndexOf("dous")!=-1){
                        // here I check the starting position is equal to length of string -4
                        // The reason is dous should be present in end of string
                        if(line.lastIndexOf("dous")==line.length()-4){
                            System.out.println(line);
                        }
                    }
                }

            }

            // Always close files.
            bufferedReader.close();
        }
        catch(FileNotFoundException ex) {
            System.out.println(
                    "Unable to open file '" +
                            fileName + "'");
        }
        catch(IOException ex) {
            System.out.println(
                    "Error reading file '"
                            + fileName + "'");

        }
    }
}

The output and code images.

In above you can see the words which have dous in end are printed.

I hope you got the answer and understand it. If any doubts ask in comments I will help in it.

Thank you:):)