A 6.85 g bullet traveling at 520 m/s embeds itself in a 1.79 kg wooden block...
A 6.85 g bullet traveling at 520 m/s embeds itself in a 1.79 kg wooden block at rest on a frictionless surface. The block is attached to a spring with k = 82.0 N/m.
A. Find the period. Express your answer with the appropriate units.
B. Find the amplitude of the subsequent simple harmonic motion. Express your answer with the appropriate units.
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A 6.85 g bullet traveling at 520 m/s embeds itself in a 1.79 kg
wooden block...
A 7.30 g bullet traveling at 490 m/s embeds itself in a 1.65 kg wooden block...
A 7.30 g bullet traveling at 490 m/s embeds itself in a 1.65 kg wooden block at rest on a frictionless surface. . The block is attached to a spring with k = 90.0 N/mFind the period.Find the amplitude of the subsequent simple harmonic motion.Find the total energy of the bullet+block+spring system before the bullet enters the block.Find the total energy of the bullet+block+spring system after the bullet enters the block.
A 2.40-g bullet embeds itself in a 1.10-kg block, which is attached to a spring of...
A 2.40-g bullet embeds itself in a 1.10-kg block, which is
attached to a spring of force constant 760 N/m .
A 2.40-g bullet embeds itself in a 1.10-kg block, which is attached to a spring of force constant 760 N/m. If the maximum compression of the spring is 5.40 cm, find the initial speed of the bullet. v_0 = m/s Find the time for the bullet-block system to come to rest. t = s
A 10.0 gram bullet traveling at 275 m/s strikes and embeds itself in a 3.490 kg...
A 10.0 gram bullet traveling at 275 m/s strikes and embeds itself in a 3.490 kg block of wood held on a frictionless table by a spring having k= 50.0 kg/sec^2. Calculate the speed of the block immediately after the collision and the compression of the spring in meters.
A bullet of mass 1.8×10−3 kg embeds itself in a wooden block with mass 0.987 kg...
A bullet of mass 1.8×10−3 kg embeds itself in a wooden block with mass 0.987 kg , which then compresses a spring (k = 150 N/m ) by a distance 5.5×10−2 m before coming to rest. The coefficient of kinetic friction between the block and table is 0.54. What is the initial speed of the bullet? Vinit==? What fraction of the bullet's initial kinetic energy is dissipated (in damage to the wooden block, rising temperature, etc.) in the collision between...
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A bullet of mass 2.0×10−3 kg embeds itself in a wooden block with mass 0.996 kg , which then compresses a spring (k = 120 N/m ) by a distance 4.5×10−2 m before coming to rest. The coefficient of kinetic friction between the block and table is 0.49. A) What is the initial speed of the bullet? B) What fraction of the bullet's initial kinetic energy is dissipated (in damage to the wooden block, rising temperature, etc.) in the collision...
A 2.40-g bullet embeds itself in a 1.20-kg block which is attached to a spring of...
A 2.40-g bullet embeds itself in a 1.20-kg block which is attached to a spring of force constant 760 N/m Part A If the maximum compression of the spring is 5.80 cm, find the initial speed of the bullet να ΑΣφ m/s Previous Answers Request Answer Submit X Incorrect; Try Again; 2 attempts remaining Part B Find the time for the bullet-block system to come to rest. ΑΣφ t = Request Answer Submit
A 10.0-g bullet is fired into, and embeds itself in, a 1.95-kg block attached to a...
A 10.0-g bullet is fired into, and embeds itself in, a 1.95-kg block attached to a spring with a force constant of 20.0 N/m and whose mass is negligible. How far is the spring compressed if the bullet has a speed of 300 m/s just before it strikes the block and the block slides on a frictionless surface? Note: You must use conservation of momentum in this problem because of the inelastic collision between the bullet and block.
A 10.0-g bullet is fired into, and embeds itself in, a 1.80-kg block attached to a...
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A 35.0 g bullet strikes a 5.5 kg stationary wooden block and embeds itself in the...
A 35.0 g bullet strikes a 5.5 kg stationary wooden block and embeds itself in the block. The block and bullet fly off together at 7.0 m/s. What was the original speed of the bullet?
A bullet of mass 0.056 kg traveling horizontally at a speed of 100 m/s embeds itself...
A bullet of mass 0.056 kg traveling horizontally at a speed of 100 m/s embeds itself in a block of mass 1.5 kg that is sitting at rest on a nearly frictionless surface. (a) What is the speed of the block after the bullet embeds itself in the block? v= m/s (b) Calculate the kinetic energy of the bullet plus the block before the collision: K; = (c) Calculate the kinetic energy of the bullet plus the block after the...
A 2.40-g bullet embeds itself in a 1.10-kg block, which is
attached to a spring of force constant 760 N/m .
A 2.40-g bullet embeds itself in a 1.10-kg block, which is attached to a spring of force constant 760 N/m. If the maximum compression of the spring is 5.40 cm, find the initial speed of the bullet. v_0 = m/s Find the time for the bullet-block system to come to rest. t = s
A 2.40-g bullet embeds itself in a 1.20-kg block which is attached to a spring of force constant 760 N/m Part A If the maximum compression of the spring is 5.80 cm, find the initial speed of the bullet να ΑΣφ m/s Previous Answers Request Answer Submit X Incorrect; Try Again; 2 attempts remaining Part B Find the time for the bullet-block system to come to rest. ΑΣφ t = Request Answer Submit
A bullet of mass 0.056 kg traveling horizontally at a speed of 100 m/s embeds itself in a block of mass 1.5 kg that is sitting at rest on a nearly frictionless surface. (a) What is the speed of the block after the bullet embeds itself in the block? v= m/s (b) Calculate the kinetic energy of the bullet plus the block before the collision: K; = (c) Calculate the kinetic energy of the bullet plus the block after the...
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