Construct a 98% confidence interval estimate for the mean μ using the given sample information. (Give your answers correct to two decimal places.)
n = 22, x = 18, and s = 2.5
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Construct a 98% confidence interval estimate for the mean μ using the given sample information. (Give...
Use the t-distribution to find a confidence interval for a mean μ given the relevant sample results. Give the best point estimate for μ, the margin of error, and the confidence interval. Assume the results come from a random sample from a population that is approximately normally distributed. A 99% confidence interval for μ using the sample results x¯=93.5, s=34.3, and n=15 Round your answer for the point estimate to one decimal place, and your answers for the margin of...
Construct the confidence interval for the population mean μ. Construct the confidence interval for the population mean μ 0.98, x: 5.9, σ: 0.6, and n: 44 A 98% confidence interval for μ is OD (Round to two decimal places as needed.)
Construct a 98% confidence interval to estimate D from the following sample information. Assume the differences are normally distributed in the population. = 39.32, sd= 27.17, n = 22 Appendix A Statistical Tables (Round your answers to 3 decimal places.) ≤ D ≤
Answers only is okay! Construct the indicated confidence interval for the population mean μ using the t-distribution. Assume the population is normally distributed. c=0.99, x=13.1, s=3.0, n= 6 Construct the indicated confidence interval for the population mean μ using the t-distribution. Assume the population is normally distributed. c=0.95, x=14.5, s=0.55, n= 15 Use the given confidence interval to find the margin of error and the sample mean. (12.7,19.9The sample mean is In a random sample of 18 people, the mean...
Construct a 98% confidence interval to estimate the population mean with x = 55 and sigma = 12 for the following sample sizes. a) n = 39 b) n = 40 c) n = 69 . a) With 98% confidence, when n = 39, the population mean is between the lower limit of nothing and the upper limit of nothing. (Round to two decimal places as needed.)
Construct a 99% confidence interval to estimate the population mean using the data below. X = 46 o = 12 n42 With 99% confidence, when n = 42 the population mean is between a lower limit of (Round to two decimal places as needed.) and an upper limit of Construct a 95% confidence interval to estimate the population mean with X = 102 and o = 25 for the following sample sizes. a) n = 32 b) n = 45...
Construct a 98% confidence interval to estimate the population mean with x=59 and σ=13 for the following sample sizes. a) n equals= 30 b) n equals= 49 c) n equals= 64 a) With 98% confidence, when n=30,the population mean is between the lower limit of blank and the upper limit of. (Round to two decimal places as needed.)
6.1.23 construct the confidence interval for the population mean μ c = 0.98, x̅ = 15.7, σ = 4.0, and n=65 A 98% confidence interval for μ is OD (Round to one decimal place as needed.)6.1.27 Use the confidence interval to find the margin of error and the sample mean (1.58,2.06) The margin of error is (Round to two decimal places as needed.)
Construct a 98% confidence interval to estimate the population mean with x 62 and o 12 for the following sample sizes. a) n 33 b)n 49 c) n 67 Click the icon to view the cumulative probabilities for the standard normal distribution a) With 98% confidence, when n 33, the population mean is between the lower limit of and the upper limit of (Round to two decimal places as needed.)
A 98% confidence interval for a population mean is given as 31.4 < μ < 40.8. Round your answers to 1 decimal place. (a) Calculate the sample mean. x = (b) Calculate the margin of error.