A capacitor is completely charged with 600 nC by a voltage source that had 325 V....
A capacitor is completely charged with 600 nC by a voltage source that had 325 V.
What is its capacitance?
The initial air gap of the capacitor above was 5 mm. What is the stored energy if the air gap is now 13 mm?
Homework Answers
capacitance C = charge/ potential = 600/325 = 1.846 nF
capacitance is inversely proportional to air gap.
so new capacitance = 1.846*5/13 =0.71 nF
hence new energy = q2 /2*C = 6002 /2*0.71 = 0.253 milli farad
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