Question

using simple and basic C++, read two strings and determine if one is an anagram of another.

Do not use include ctype

Do not use cctype

Answer 1

C++ code for the above question-

#include<bits/stdc++.h>

using namespace std;

int main() {

   string s1,s2;
   cin>>s1>>s2; // input both strings

   int a[26]={0},b[26]={0}; // for counting the number of occurance of each alphabet

   for(int i=0;i<s1.length();i++){
       a[s1[i]-'a']++; // counting the occurance of each alphabet in s1
   }
   for(int i=0;i<s2.length();i++){
       b[s2[i]-'a']++; // counting the occurance of each alphabet in s2
   }

   //check if all alphabet occurs equal number of times.
   int flag=0;
   for(int i=0;i<26;i++){
       if(a[i]!=b[i]){ // checking if the count of a particular alphabet
                       //in both string is different
           flag=1;
           break;
       }
   }

   if(flag==0){
       cout<<"One string is anagram of other.";
   }
   else{
       cout<<"One string is not the anagram of other.";
   }

return 0;
}

Code-

Input and Output-

Explanation-

One string is the anagram of other if the number of occurance of each alphabet in both string is same. So,in the above code,first the number of occurance of each alphabet for both string s1 and s2 is calculated in array a and b respectively.Then,I have checked if the count of each alphabet in array a and b is same or not.

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