Question 1) Use the confidence level and sample data to
find the margin of error E. Round your answer to the same number of
decimal places as the sample mean unless otherwise
noted.
The duration of telephone calls directed by a local telephone
company: Round your answer to the nearest
thousandth.
Question 1) Use the confidence level and sample data to find the margin of error E....
1. Use the given degree of confidence and sample data to construct a confidence interval for the point) population proportion p. A survey of 865 voters in one state reveals that 408 favor approval of an issue before the legislature. Construct the 95% confidence interval for the true proportion of all voters in the state who favor approval. 0 0.438<p0.505 0 0.444 p0.500 0 0.435<p<0.508 O 0.471 p0.472 2. Use the given data to find the minimum sample size required...
confidence level and sample data to find confidence interval
for estimating a population round your answer to the same number of
decimal places as a sample
Question 2 2 pts Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. 90% confidence; n 390, x-146
Use the confidence level and sample data to find the margin of error, E, for 2TT If an interval estimate of the mean life, in hours, of light bulbs is 100 to 280 hours, then determine the margin of error. (a) 230 hours (b) 90 hours (c) 50 hours (d) 180 hours
Use the confidence interval to find the margin of error and the sample mean. (1.76,2.00) The margin of error is □ Round to two decimal places as needed.) The sample mean is Type an integer or a decimal.) Find the minimum sample size n needed to estimate μ for the given values of c. and E. cz 0.90, ơ 7.9, and E-2 Assume that a preliminary sample has at least 30 members. n-Round up to the nearest whole number )
Question 13 (1 point) Saved Use the confidence level and sample data to find a confidence interval for estimating the population μ. Round your answer to the same number of decimal places as the sample mean. A laboratory tested 82 chicken eggs and found that the mean amount of cholesterol was 228 milligrams with σ-19 milligrams. Construct a 95% confidence interval for the true mean cholesterol content, μ, of all such eggs. (1224 mg < μ < 232 mg 223...
Use the given confidence level and sample data to find (a) the margin of error and (b) the confidence interval for the population mean u. Assume that the population has a normal distribution. Weight lost on a diet: 90% confidence; n 20, x= 7.0 kg, s 9.2 kg. Click the icon to view a table of critical t-values. kg (Round to one decimal place as needed.) (a) E (b) What is the confidence interval for the population mean u? kg<u...
Use the confidence level and sample data to find a confidence interval for estimating the population . Round your answer to the same number of decimal places as the sample mean. Test scores: n = 104, 7 = 95.3, 0 = 6.5; 99% confidence 93.7 < < 96.9 O94.1 << 96.5 93.8 < p < 96.8 94.2 << 96.4
Question 36 4 pts Use the confidence level and sample data to find a confidence interval for estimating the population P. Round your answer to the same number of decimal places as the sample mean. Test scores n-72 x=581, 0 = 6.2, 98% confidence 56.2 <<60.0 0 56.4 < p < 59.8 56.9< < 59.3 56.7 <<59.5
QUESTION 8 Use the confidence level and sample data to find a confidence interval for estimating the population u. Round your answer to the same numbe of decimal places as the sample mean. A random sample of 1 17 full grown lobsters had a mean weight of 22 ounces and a standard deviation of 2.7 ounces. Construct a 98% confidence interval for the population mean . ?20 oz < ? < 22 oz 022 oz < ? < 24 oz...
Use the given margin of error, confidence level, and population standard deviation, sigmaσ, to find the minimum sample size required to estimate an unknown population mean, muμ. Margin of error: 1.91.9 inches, confidence level: 9595%, sigmaσequals=2.62.6 inches A confidence level of 9595% requires a mimimum sample size of nothing. (Round up to the nearest integer.)