Ans :
Using ideal gas law pV = nRT
p = 25 atm
V = 100 L
R = 0.0821 L.atm/mol.K
T = 80 degree Celsius = 353.15 K
putting values :
25 atm x 100 L = n x 0.0821 L.atm/mol.K x 353.15 K
n = 86.2 mol
mass of ethane = mol x molar mass
= 86.2 mol x 30.07 g/mol
= 2592.8 grams ethane
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