Question

mathTutor
Write a program that selects two random numbers -20 to 20. The two numbers would get displayed with "+" between them. The user should enter the sum of the two numbers.
The program should print "Incorrect" if the user enters a wrong answer and re-prompts the user to re-enter the answer again. Limit the number of incorrect tries to 3. After 3 incorrect tries print the correct answer. The program should print a message like "Correct!" if the user enters the right answer.  

The program would then display "Would you like another problem y/n? ". If user selects "y" or "Y" you show them another problem to be solved.

Answer 1

Here is code:

#include <iostream>

#include <stdlib.h> /* srand, rand */

#include <time.h> /* time */

using namespace std;

int main()

{

int minRange = -20,

maxRange = 20,

num1,

num2,

result,

answer,

tries = 0;

char choice;

srand(time(NULL));

do

{

tries = 0;

// get random numbers

num1 = minRange + (rand() % (maxRange - minRange + 1));

num2 = minRange + (rand() % (maxRange - minRange + 1));

answer = num1 + num2;

cout << "What the sum of " << num1 << " + " << num2 << " = ";

// read result

cin >> result;

do

{

tries++;

if (result == answer)

{

cout << "correct\n";

break;

}

else if (tries == 3)

{

cout << "Correct answer is : " << answer << endl;

break;

}

cout << "Incorrect, Try again : ";

cin >> result;

} while (tries != 3); // if incorrect then loop again

cout << "\nWould you like another problem y/n? : ";

cin >> choice;

} while (choice == 'Y' || choice == 'y');

}

Output: