A 14.0-m length of wire consists of 6.0 m of copper followed by 8.0 m of...
A 14.0-m length of wire consists of 6.0 m of copper followed by 8.0 m of aluminum, both of diameter 1.1 mm . A voltage difference of 95 mV is placed across the composite wire. The resistivity of copper is 1.68×10−8Ω⋅m and the resistivity of aluminum is 2.65×10−8Ω⋅m.
Part A) What is the total resistance (sum) of the two wires? Express your answer to two significant figures and include the appropriate units.
Part B) What is the current through the wire?
Part C) What is the voltage across the copper part?
Part D) What is the voltage across the aluminum part?
Homework Answers
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A 14.0-m length of wire consists of 6.0 m of copper followed by
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A 18.0-m length of wire consists of 9.0 m of copper followed by 9.0 m of aluminum, both of diameter 1.5 mm . A voltage difference of 75 mV is placed across the composite wire. The resistivity of copper is 1.68×10−8Ω⋅m and the resistivity of aluminum is 2.65×10−8Ω⋅m. A. What is the voltage across the copper part? B. What is the voltage across the aluminum part?
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Calculate the ratio of the resistance of 12.0 m of aluminum wire 2.4 mm in diameter, to 26.0 m of copper wire 1.8 mm in diameter. The resistivity of copper is 1.68× 10 −8 Ω⋅m and the resistivity of aluminum is 2.65× 10 −8 Ω⋅m .
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