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(Anions) a student added barium ion, Ba2+ to an aqueous solution and observed the formation of...

(Anions) a student added barium ion, Ba2+ to an aqueous solution and observed the formation of a precipitate. The subsequent addition of nitric acid, HNO3, had no effect on the precipitate. What anion was present in the original solution? Explain how you made your determination
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Answer #1

Anion present in the solution is Sulphate anion (SO​​​​​42-​) .

Barium ion can react with sulphate anion to form barium sulphate which can exist as a white precipitate. Subsequent addition of nitric acid to this solution will not make any effect on the barium sulphate precipitate. Even sulphite and carbonate can also form white precipitate with Barium ion as barium sulphite and barium carbonate respectively. But both of them will react with nitric acid. So the anion present in the aqueous solution is sulphate. Reactions are given below.

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