If the modulus of elasticity of an elliptical hair is 3.75 GPa. The dimensions of the...
If the modulus of elasticity of an elliptical hair is 3.75 GPa. The dimensions of the hair are A = 40μ, B=30 μ. The stress at which a hair breaks is called the breaking stress. Suppose this hair broke under a load of 88 grams. What was the breaking stress?
Homework Answers
Applied load=88 gms=0.088*9.8=0.86 N
Area of sueface on which the load is applied=(40*10^-6)*(30*10^-6)=1.2*10^-9 m²
Stress= force /area=0.86/(1.2*10^-9)=0.717*10^9 Pa=0.717 GPa
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If the modulus of elasticity of an elliptical hair is 3.75 GPa.
The dimensions of the...
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