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A game has the following rules: An unbalanced coin is flipped 4 times. If two heads...

A game has the following rules: An unbalanced coin is flipped 4 times. If two heads come up then you are paid 10 dollars. Otherwise, you must pay 2 dollars. The expected average payoff per game is 0 dollars per game. Find the probability of getting ahead if you flip the coin once. Round your answer to the nearest 1000th of a percent.

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Answer #1

Payoff= P(head)*10-P(tail)*2

P(head) = x

P(tail) = 1-x

P(head) = 0.1667

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