assume that a procedure yields a binomial distribution with a trial repeated n times. use the binomial probability formula to find the probability of x successes given the probability p of success on a single trial
n=16, x=12,p=0.75
p(12)=
How do I use my calculator? What is the ! on the calculator? can u use stat cruch for this problem?
Solution :
Given that ,
p = 0.75
1 - p = 1 -0.5 = 0.25
n = 16
x = 12
Using binomial probability formula ,
P(X = x) = ((n! / (n - x)!) * px * (1 - p)n - x
P(X = 12 ) = (16! / (16 - 12)!) * 0.7512 * 0.25)16 - 12
= 0.2252
Probability = 0.2252
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