Question

HW Help? I cannot seem to figure this one out..

--Write a program that reads the integers between 1 and 100 and counts the occurrences of each. assume the input ends with 0.

Example: 2 5 6 5 4 3 23 43 2 0 ENTER

2 occurs 2 times

3 occurs 1 time

4 occurs 1 time

5 occurs 2 times

6 occurs 1 time

23 occurs 1 time

43 occurs 1 time

Note that if a number occurs more than one time, the plural word times is used in the output.--

Answer 1

Java Code for the given question:

import java.util.Scanner;

public class Base1 {

      public static void main(String[] args) {

            //Scanner class to get the input from user

            Scanner scan = new Scanner(System.in);

            System.out.println("Enter the integers between 1 to 100 and end with 0");

            String input = scan.nextLine();

            String[] integerStrings = input.split(" ");

            int[] integers = new int[integerStrings.length];

            // Creates the integer array.

            for (int i = 0; i < integers.length; i++){

                integers[i] = Integer.parseInt(integerStrings[i]);

            //Parses the integer for each string.

            }

            //Iterating over 1 to 100 to find the number of times each number occured

            for (int i = 1; i<=100; i++){

                  int count =0;

                  for(int j:integers){

                        if (i==j){

                              count++;

                        }

                  }

                  if (count==1){

                        System.out.println(i+" occurs "+count+" time");

                  }

                  else if(count>1){

                        System.out.println(i+" occurs "+count+" times");

                  }

            }

            //Closing the scanner function

            scan.close();

      }

}

Output: