Write a pseudocode algorithm to search for a value in a graph (you can assume that each node v has a value field i.e. v.value). Compute the time complexity of your algorithm
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We can simply use BFS to search for a value
BFS (G, s,x) //Where G is the graph and s is the source node let Q be queue. Q.enqueue( s ) //Inserting s in queue until all its neighbour vertices are marked. if(s.value==x) return true; mark s as visited. while ( Q is not empty) //Removing that vertex from queue,whose neighbour will be visited now v = Q.dequeue( ) //processing all the neighbours of v for all neighbours w of v in Graph G if w is not visited Q.enqueue( w ) //Stores w in Q to further visit its neighbour /*---------------------------- */ if(w.value==x) return true; mark w as visited.
The time complexity of BFS is O(V + E), where V is the number of nodes and E is the number of edges.
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