A CD-ROM drive in a computer spins the 12-cm-diameter disks at 9900 rpm. 1) What is...
A CD-ROM drive in a computer spins the 12-cm-diameter disks at 9900 rpm.
1) What is a disk's period (in s) ?
2) What is a disk's frequency (in rev/s)?
3) What is the acceleration in units of g that this speck of dust experiences?
Homework Answers
Angular speed = 9900 rpm = 9900×2×pi/60 rad/s
W = 1036.725 rad/s
1)Time period T = 2×pi/w = 0.00606 s
2)Frequency = 1/T = 1/0.00606 = 165 Hz
F = 165 rev/s
3) a = w2 r = 1036.725×1036.725×0.06 = 64488 m/s2 = 6580.4g
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