Question

The reaction A(g)⇌2B(g) has an equilibrium constant of K = 0.010. What is the equilibrium constant...

The reaction A(g)⇌2B(g) has an equilibrium constant of K = 0.010. What is the equilibrium constant for the reaction B(g)⇌12A(g)?

Express your answer using two significant figures.

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Answer #1

A(g) <----------> 2B(g)

K1 = [B]^2 / [A] = 0.010

B (g)   <-----------> 1/2 A (g)

K = [A]^1/2 / [B]

    = sqrt (1 / K1)

   = sqrt (1/ 0.010)

K = 10

equilibrium constant = 1.0 x10^1

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