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Implement function allEven() that takes a list of integers and returns True if all integers in...

  1. Implement function allEven() that takes a list of integers and returns True if all integers in the list are even, and False otherwise.

>>> allEven([8, 0, -2, 4, -6, 10])

True

>>> allEven([8, 0, -1, 4, -6, 10])

False

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Answer #1

The below function takes list of integers.

def allEven(Lst):
   flag = 0
   for number in Lst:
       if abs(number)%2 !=0:
           flag = 1
           print('false')
           break
   if flag ==0:
       print('true')

Lst refers to the list of integers and number refers to the loop iterator.

The loop in the function takes one number at a time and applies absolute function to get positive value then it applies odd number condition. If it is true then it updates flag to 1 and displays 'false' and breaks from the loop to avoid further computation. If flag is 0 then all are even 'true' will be displayed.

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