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An object has an initial momentum of 57.4 kgm/s to the right. A force is then...

An object has an initial momentum of 57.4 kgm/s to the right. A force is then exerted on the object in the opposite direction over a period of time which, resulting in its final momentum of 22.5 kgm/s to the left. What is the impulse acting on this object? Enter the units as N*s and assume right to be the positive direction.

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Answer #1

impulse is given by

I = ( P2 - P1)

I = ( - 22.5 - 57.4)

i = - 79.9 Ns

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