A hydroelectric power plant has a dam 100 ft high, and water can flow through the...
A hydroelectric power plant has a dam 100 ft high, and water can flow through the dam and water turbines at 1 million lbm per minute over a 60-ft drop. If the turbines can convert the loss in potential energy of the water into electric power at an efficiency of 70%, how much power can the facility produce in megawatts? (Note: 550 ft ·lbf/s = 1 hp = 0.746 kW)
Homework Answers
efficiency = Electric power / change in potential energy
i.e.
Electric power = 0.7* change in Potential energy
= 0.7* [60* 106/60 ]
= 0.7*106 * 0.746 /550 KW (conversion as mentioned in question )
= 0.949 MW
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