Question

Required functions def inputWithinRange (lowValue, highValue): This function will ask for a number from the keyboard. The function will only return a value that is within the inclusive range of lowValue to highValue. If the entered value is not within the provided range, the function will ask again until the user has entered an acceptable value. The function will return the accepted value. def doContinue (prompt): This function will ask for a string using the prompt parameter. The function will return True if the user enters an upper or lower case “yes” or False if the user enters an upper or lower case “no”. Any other entered value will cause the function to ask again until an acceptable value has been entered. def square (intValue): This function returns the square of intValue. def summation (intValue): This function returns the summation of 1 to intValue. You can assume that intValue will be positive. For example, summation (5) would return 15 (1 + 2 + 3 + 4 + 5). def sumOfSquare (intValue): This function return the sum of the squares from 1 to intValue. For example, sumOfSquares(5) would return 55 (1 + 4 + 9 + 16 + 25). You MUST use a loop and the square function to determine the returned value. def factorial (intValue): This function returns the factorial of 1 to intValue. You can assume that intValue will be positive. For example, factorial (5) would return 120 (1 * 2 * 3 * 4 * 5). def distance (x1, y1, x2, y2): This function returns the distance between two points. x1, y1 will be the first point, and x2, y2 will be the second point. The formula is distance = . You will want to look at the functions offered by the Math class to help with this formula. def isOdd (int intValue): This function will return True if intValue is odd, otherwise it returns False. def isEven (intValue): This function will return True if intValue is even, otherwise it return False. This function MUST use isOdd to determine the returned value. The point behind this function is to minimize the amount of redundant work that is done in our code, not that determining odd or even is a lot of work. It’s the concept more than the reality of the code in this case.

Answer 1

code:

# importing the maths library
import math


# functions check if the input is in the provided range or not
# and returns the number if in range
def inputWithinRange (lowValue, highValue):

    while True: # using while loop for asking continously until funtion returns
        num = int(input('Enter an integer value within the range given: '))

        if num >= lowValue and num <= highValue:
            return num


# function check if user enters 'yes' or 'no'
def doContinue ():

    while True: # while loop will run till the conditions are satisfied
        string = input('Do you want to continue: ')

        if string.lower() == 'yes' :
            return True

        elif string.lower() == 'no' :
            return False


# function returns the square of given number
def square (intValue):

    return intValue ** 2


# function returns the sum of the first n numbers, where n is provided by user
def summation (intValue):

    summation = 0   # variable to store sum

    for i in range(1, intValue + 1):    # for loop will iterate from 1 to intValue incluesive
        summation += i

    return summation


# functoin returns the sum of squares of first n numbers, where n is provided by user
def sumOfSquare (intValue):

    sumOfSquare = 0 # variable to store sum of squares

    for i in range(1, intValue + 1):    # for loop will iterate from 1 to intValue incluesive
        sumOfSquare += square(i)    # here we have used previously defined function to find square of each number

    return sumOfSquare


# function to return the factorial of a given number
def factorial (intValue):

    factorial = 1   # intializing the factorial to 1

    if intValue <= 1 :  # if number is less or equal to 1 we return factorial
        return factorial

    else:
        for i in range(2, intValue):
            factorial *= i

        return factorial


# function for calculating and returning the distance between two points provided
def distance (x1, y1, x2, y2):

    distance = math.sqrt((x2 - x1)**2 + (y2 - y1)**2)   # using the formua for calculating distance

    return distance


# functoin checks if the provided number is odd or not
def isOdd (intValue):

    if intValue % 2 == 0:   # if odd return true
        return True

    else:   # else return false
        return False


# function checks if the provided number is even or not
def isEven (intValue):

    if isOdd(intValue): # if number is odd return false
        return False

    else:   # else number is even return true
        return True

For help please comment.
For modification please comment.

Thank you.