Consider the following system at equilibrium where Kc
= 7.00×10-5and delta H° =
182 kJ/mol at 673 K.
NH4I (s) =
NH3(g) + HI (g)
The production of NH3(g) is favored
by:
Indicate True (T) or False (F)
for each of the following:
___TF 1. decreasing the
temperature.
___TF 2. decreasing the pressure
(by changing the volume).
___TF 3. decreasing the
volume.
___TF 4. adding
NH4I .
___TF 5. removing
HI .
Submit Answer
According to Le chatlier's principle whenever a constraint is applied to a system at equilibrium the system would try to annul the effect of the constraint. The word constraint means a change in temperature ,pressure or change in concentration of the system
1) False
In the present equilibrium the forward reaction is endothermic that is (proceeds by absorption of temperature )if the temperature of such a system is decreased ,the system would try to resist that effect by favoring the backward reaction,which is exothermic i.e that is NH4I doesn't decompose (less ammonia formation)
2)True
The present equilibrium proceeds by an increase in the number of moles of the product therefore an increase of the pressure of the system .When we decrease the pressure the system would try to resist that change by undergoing forward reaction.(Decrease in pressure favors forward reaction)
3)False
Here the forward reaction is accompanied by increase in the number of moles of the products.when we decrease the volume the no. of moles per unit volume increases.According to Le chatlier's principle the system would try to increase the No. of moles per unit volume.this is possible only by the backward reaction (Ammonia formation less favored)
4)True
By adding NH4I we are increasing the concentration of the reactant .According to Le chatlier's principle to reduce the concentration of the reactant forward reaction takes place.that is Ammonia formation takes place
5)True
By removing the HI we are changing the concentration of the product so to cancel that effect more NH4I is decomposed to Ammonia( NH3 )and HI
Consider the following system at equilibrium where Kc = 7.00×10-5and delta H° = 182 kJ/mol at...
Consider the following system at equilibrium where Kc = 7.00×10-5and H° = 182 kJ/mol at 673 K. NH4I (s) - NH3(g) + HI (g) The production of NH3(g) is favored by: Indicate True (T) or False (F) for each of the following: ___TF 1. increasing the temperature. ___TF 2. decreasing the pressure (by changing the volume). ___TF 3. increasing the volume. ___TF 4. adding NH4I . ___TF 5. removing HI
Consider the following system at equilibrium where Kc = 1.80×10-2and H° = 10.4 kJ/mol at 698 K. 2 HI (g) -->H2(g) + I2(g) The production of H2(g) is favored by: Indicate True (T) or False (F) for each of the following: ___TF 1. increasing the temperature. ___TF 2. increasing the pressure (by changing the volume). ___TF 3. increasing the volume. ___TF 4. removing HI . ___TF 5. adding I2. Consider the following system at equilibrium where Kc = 55.6 and...
Please do I do rate :) Consider the following system at equilibrium where Kc = 7.00x10-5 and AH° = 182 kJ/mol at 673 K. ? NH4I (s) NH3 (g) + HI (g) The production of NH3 (g) is favored by: Indicate True (T) or False (F) for each of the following: 1. increasing the temperature. A2. decreasing the pressure (by changing the volume). 3. increasing the volume. A4. adding NH4I. 5. removing HI.
Consider the following system at equilibrium where Kc = 1.80×10-2and delta H° = 10.4 kJ/mol at 698 K. 2 HI (g) goes to H2(g) + I2(g) The production of H2(g) is favored by: Indicate True (T) or False (F) for each of the following: ___TF 1. increasing the temperature. ___TF 2. increasing the pressure (by changing the volume). ___TF 3. increasing the volume. ___TF 4. removing HI . ___TF 5. removing I2.
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Consider the following system at equilibrium where Kc = 6.50×10-3 and H° = 16.1 kJ/mol at 298 K. 2 NOBr (g) 2 NO (g) + Br2 (g) The production of NO (g) is favored by: Indicate True (T) or False (F) for each of the following: 1. increasing the temperature. 2. increasing the pressure (by changing the volume). 3. increasing the volume. 4. adding NOBr . 5. removing Br2 .
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