Let X be a discrete random variable. If Pr(X<9) = 2/9, and Pr(X<=9) = 6/18, then what is Pr(X=9)? Please specify your answer in decimal terms and round your answer to the nearest hundredth (e.g., enter 12 percent as 0.12
Solution:
Pr(X<9) = 2/9
Pr(X<=9) = 6/18
Given that X is a discrete random variable.
Pr(X<=9) = Pr(X<9) + P(X = 9)
So ,
P(X = 9) = Pr(X<=9) - Pr(X<9)
= (6/18) - (2/9)
= 2/18
= 1/9
= 0.11
P(X = 9) = 0.11
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