What would be the effect on the volume of an ideal gas if the pressure is doubled and the temperature in kelvins is halved? Defend this response.
use combined gas law:
Pi*Vi/Ti = Pf*Vf/Tf
Given:
Pf = 2*Pi
Tf = Ti/2
use:
Pi*Vi/Ti = Pf*Vf/Tf
Pi*Vi/Ti = 2*Pi*Vf/(Ti/2)
Pi*Vi/Ti = 4*Pi*Vf/Ti
Vi = 4Vf
Vf=Vi/4
Answer:
Volume becomes 1/4 times the initial value
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