The x, y, and z components of a magnetic field are Bx = 0.10 T, By = 0.14 T, and Bz = 0.17 T. A 25-cm wire is oriented along the z axis and carries a current of 4.4 A. What is the magnitude of the magnetic force that acts on this wire?
we will calculate magnetic force due to each component separately
Bx = 0.10 T, By = 0.14 T, Bz = 0.17 T
L= 25 cm = 0.25 m
I = 4.4 A
Current is flowing along the z-axis
due to Bx first
the angle between Bx and current is 90 degree
F = I*Bx*L Sin 90
F = (4.4)(0.10)(0.25) Sin90
F = 0.11 N
using Right hand rule we can see that its direction will be along y axis
due to By
the angle between By and current is 90 degree
F = I*Bx*L Sin 90
F = (4.4)(0.14)(0.25) Sin90
F = 0.154 N
using Right-hand rule we can see that its direction will be along -x-axis
due to Bz
the angle between Bx and current is 0 so force F will also be zero
so we have two components of F both are perpendicular to each other
as one is along the y-axis and another is along -x-axis
we can find out magnitude using this
F = sqrt(Fx^2 + Fy^2)
F = sqrt((0.154^2) + (0.11^2))
F = 0.189 N
The x, y, and z components of a magnetic field are Bx = 0.10 T, By...
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