Question

THIS IS A PROGRAM FOR PYTHON

THIS IS A PROGRAM FOR PYTHON

THIS IS A PROGRAM FOR PYTHON

This time, we will write a program that uses functions to parse through all those names in a List object (see below for the "us_counties" list) to count the number of occurrences each vowel (a, e, i, o, u) has in all the names. We want 5 separate answers, one for each vowel. Not looking for output here.

All my solution will do is display the final results being returned from the function, holding each one of the 5 counts.

To solve this problem, you'll want to create a for-loop that goes through the five values, then call the function inside the loop. Each time through the loop, make a new entry in a dictionary, with the letter as the key and the count as the value.

Remember dictionary notation:

d = {} to create an empty dictionary

d['a'] = 5 # to set/modify the value associated with the key 'a' to the number 5.

us_counties = ['Autauga','Baldwin','Barbour','Bibb','Blount','Bullock','Butler','Calhoun','Chambers','Cherokee','Chilton']

Answer 1

Here is the completed code for this problem. Comments are included, go through it, learn how things work and let me know if you have any doubts or if you need anything to change. If you are satisfied with the solution, please rate the answer. If not, PLEASE let me know before you rate, I’ll help you fix whatever issues. Thanks

Note: Please maintain proper code spacing (indentation), just copy the code part and paste it in your compiler/IDE directly, no modifications required.

#code

'''
This method will take a list of strings, count the number of vowels in each string
add them to a dict and return the dict
'''
def count_vowels(data_list):
    #creating a list of vowels
    vowels=['a','e','i','o','u']
    #creating an empty dict
    count_dict={}
    #looping through each vowel in vowels list
    for i in vowels:
        #adding to the dict with key being the vowel and value being 0
        count_dict[i]=0
    #looping through each word in data_list
    for word in data_list:
        #looping through each character in current word, converted to lower case
        #to implement case insensitive check
        for c in word.lower():
            #checking if c is a vowel (c exist on vowels list)
            if c in vowels:
                #incementing the counter associated with key=current character
                count_dict[c]+=1
    #returning the count_dict
    return count_dict


#testing the above method by creating a list of us countries, calling and printing count_vowels(us_counties)
#remove these statements if you do not want to test.
us_counties = ['Autauga','Baldwin','Barbour','Bibb','Blount','Bullock','Butler','Calhoun','Chambers','Cherokee','Chilton']
print(count_vowels(us_counties))

#output

{'a': 7, 'e': 5, 'i': 3, 'o': 6, 'u': 7}