Calculate the freezing point and boiling point of a solution containing 8.25 gg of ethylene glycol (C2H6O2)(C2H6O2) in 92.4 mLmL of ethanol. Ethanol has a density of 0.789 g/cm3g/cm3.
Calculate the freezing point of the solution.
Calculate the boiling point of the solution.
These values can be calculated using the following formulae:
Where m is the molality of the solute (ethylene glycol) and keb is the ebulloscopic constant of ethanol (1.07 K*kg/mol)
Where kcryo is the cryoscopic constant of ethanol (1.99 K*kg/mol). W
We need to calculate the molality of ethyleneglycol. For this, we need the number of moles:
And the number of kg of ethanol:
The molality is then:
We can then calculate:
Which is the same as an increase in 1.95 °C, since the normal boiling temperature of ethanol is 78.4°C, the boiling point of this solution will be 80.4°C.
The normal freezing point of ethanol is -114.1°C, so the freezing point of the solution is -117.7 °C.
Calculate the freezing point and boiling point of a solution containing 8.25 gg of ethylene glycol...
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