The reaction mechanism that has been proposed for the
decomposition of H2O2 by iodide ion is:
H2O2 + I-
→ H2O +
IO-
(slow)
H2O2 + IO-
→ H2O + O2 +
I- (fast)
Which one of the following statements is true?
Select one:
a. The reaction is second order with respect to I-.
b. I- is an intermediate.
c. The reaction is first order with respect to I-.
d. IO- is a catalyst.
e. The reaction is zero order with respect to I-.
The reaction mechanism that has been proposed for the decomposition of H2O2 by iodide ion is:...
5) rate = K[A][B] Question 11 (1 point) The reaction mechanism proposed for the decomposition of H202 H2O2 + 12 -> H2O + 10-1 (slow) H2O2 + 10-1 --> H2O + O2 + 12 (fast) Which statement is true? 1) The reaction is second order in 1 2) is an intermediate 3) The reaction is first order in and first order in H2O2. 4) 10 1 is a catalyst. 5) The reaction is zero order in ! Question 12110
6. The decomposition of ozone in the upper atmosphere is catalyzed by NO. The overall reaction and rate law are: O:(g) + O(g) →202(g): rate = k[O][NOJ Write a possible mechanism that is consistent with rate law and identify an intermediate in the reaction. 7. A possible mechanism for the iodide ion catalyzed decomposition of hydrogen peroxide in aqueous solution is: H2O2(aq) + I'(aq) → H2O(l) + Of(aq) ---...-slow H2O2(aq) + Or(aq) → H2O(0) + O2(g) + I'(aq) -----fast What...
The decomposition of hydrogen peroxide (H2O2(aq)) is proposed to follow a reaction mechanism of Step 1: H2O2(aq) + Br(aq)-H2O(l) + BrO (aq) Step 2: Bro (aq) + H2O2(aq),H2O(l) + O2(g) + Br(aq) What is the catalyst, and what is the effect of having a catalyst present? Periodic Table and Datasheet Br is the catalyst, and the reaction follows a faster pathway with Br than without BrO is the catalyst, and the reaction follows a faster pathway with Bro-than without Bro...
i. For the reaction: 2H202→ 2H2O+O2 a proposed mechanism is: H2O2 + H3O2+ → H2O + H30+ +02 (a) The intermediate in the proposed mechanism is The catalyst is (b) Apply the steady state approximation to this mechanism to deduce the rate law in terms of d[O2]/dt. (15 pts)
A mechanism for the catalyzed decomposition of H2O2 is given below: step 1: H2O2(aq) + I−(aq) ➝ H2O(ℓ) + IO−(aq) step 2: IO−(aq) + H2O2(aq) ➝ H2O(ℓ) + O2(g) + I−(aq) Which species is the intermediate?
The following mechanism, proposed for the decomposition of hydrogen peroxide is composed of 2 elementary steps: H2O2(aq) + I'(aq) > H2O(l) + 10 (aq) 10 (aq) + H2O2(aq) -> H2O(l) + O2(g) + I'(aq) The rate law predicted by the mechanism is slow fast a) rate = k [H2O2) b) rate =k [H202][I] c) rate =k [H2O2][10] d) rate = k [H202) [1]
1. The mechanism for hydrogen peroxide decomposition is thought to occur in two step: step 1: H2O2+ I ------> IO + H2O step 2: IO + H2O2 --------> I + H2O + O2 a. describe each step in the mechanism as unimolecular ,bimolecular or termolecular ? b. which species in the mechanism acts as an intermediate.? c. which species in the mechanism acts as catalyst.? d. what is the net reaction?
question 12 & 13 12. The following reaction is second order in respect to CH3COOCH3. The rate constant is 2.0 X 103 L/(mol s), what is the concentration of the CH3COOCH3 after 4 minutes if the initial concentration of CH3COOCH3 is 0.25 M? CH3COOCH3 OH CH3COOCH3OH o inao si odool ni 00 o otil-lipd & aart noisassno shoo Aa noitbe 0 PJE (slow) 20 13. Hydrogen peroxide and iodide ion react in the following steps. H2O2 (aq) I' (aq) I0...
Only have iodine. Not H2O2 The following mechanism has been proposed for this reaction: HO+ I IO+ HO H.O, + IO + HO + O If this mechanism is correct, which step must be the rate-determining step? Explain.
4. The following mechanism has been suggested for the decomposition of ozone, Os. 0:(9) 02(g) +O(g) (fast equilibrium) O(g) + O2(g) → 20 (9) (slow) Consider the following statements in light of this mechanism: 1. The rate law is second order in O. 2. The rate does not depend on the concentration of Oz 3. The reaction slows with increased O, concentration 4. The rate law is second order 5. substances reacting with O atoms will speed up the reaction...