5. Consider base 2.
What is log 128
What is log 256
what is log 64
What is log 32
6. Draw the diagram showing a function is
injective
7. Draw the diagram showing a function
surjective
8. What is the
floor of sqrt ( 2)
=
ceiling of 28/6,
=
floor of sqrt ( 5 )
=
ceiling of 32/3 =
`Hey,
Note: Brother if you have any queries related the answer please do comment. I would be very happy to resolve all your queries.
5)
a)
log(128)=log(2^7)=7*log(2)
We know that log(2) is 1
So,
log(128)=7
b)
log(256)=log(2^8)=8*log(2)
We know that log(2) is 1
So,
log(256)=8
c)
log(64)=log(2^6)=6*log(2)
We know that log(2) is 1
So,
log(64)=6
d)
log(32)=log(2^5)=5*log(2)
We know that log(2) is 1
So,
log(32)=5
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5. Consider base 2. What is log 128 What is log 256 what is log 64...
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