Ka 1.4 × 10−4 M of CHmCH(OH)COOH
What is the the pH of a 0.20-M aqueous solution of lactic acid.
what is the molarity of unreacted lactic acid in the solution?
Ka 1.4 × 10−4 M of CHmCH(OH)COOH What is the the pH of a 0.20-M aqueous...
a) calculate the ph of a .20 M aqueous solution of lactic acid CH3CH(OH)COOH, the value of ka is 1.4 x 10^-4 M and it is at 25c b) what is the molarity of unreacted lactic acid in the solution?
QUESTION 3 Lactic acid, CH3CH(OH)cooH, is a weak acid with Ka 1.4x10-4. The pH of a 0.250 M solution of lactic acid is and percent dissociation of this acid is %. (Fill in the blanks. Show the numbers only. Report both of the numbers with 2 significant figures)
Lactic acid, HC3H5O3 , is a weak acid in aqueous solution, Ka = 1.4 × 10−4 . Calculate Kb for the lactate ion, C3H5O –
Lactic acid (CH3CH(OH)COOH) has only one acidic hydrogen which can dissociate as follows: CH3CH(OH)COOH (aq) + H20 (1) --- H30+ (aq) + CH3CH(OH)COO (aq) A 0.10 M solution of lactic acid has a pH of 2.44. Calculate the Ka. Ка? 10^
The weak acid C,H,OH has a Ka of 1.6 x 10-10. If a 1.4 M solution of the acid is prepared, what is the pH of the solution? The equilibrium expression is: C6H,OH(aq) + H2O(l) — H,0+(aq) + CH 0-(aq) • Round your answer to two decimal places. Provide your answer below: pH=
Determine the pH of a 0.20 M KCHO2 (potassium formate) aqueous solution. [Ka for HCHO2 = 1.8 x 10-4]. Use ice table.
Lactic acid (CH3CH(OH)COOH) has one acidic hydrogen. A 0.10 M solution of lactic acid has a pH of 2.44. Calculate Ka. Express your answer using two significant figures. Ka= Please show all work thanks
Lactic acid is found in muscles after exercising and has a Ka = 1.4 x 10-4. A 350.0 mL solution contains 0.060 moles of lactic acid and 0.040 moles of sodium lactate. What is the pH of the solution after the addition of 0.015 moles of HNO3?
27. What is the pH of an aqueous solution that contains 0.35 M of lactic acid, HC3H5O2, (Ka = 4.4 X 10 -4 ) and 0.55 M of Nat C3H5O2 - ? a. 2.77 b. 3.55 C. 4.65 d. 7.35 e. 5.89
Calculate the pH of a 0.0140 M aqueous solution of formic acid (HCOOH, Ka = 1.8×10-4). pH =