Question

A proton, traveling with a velocity of 3.1 × 10⁶ m/s due east, experiences a magnetic force that has a maximum magnitude of 6.6 × 10^-14 N and direction of due south. What are the magnitude and direction of the magnetic field causing the force? If the field is up, then enter a number greater than zero. If the field is down, then enter a number less than zero.

An α-particle has a charge of +2e and a mass of 6.64 × 10^-27 kg. It is accelerated from rest through a potential difference that has a value of 1.19 × 10⁶ V and then enters a uniform magnetic field whose magnitude is 3.12 T. The α-particle moves perpendicular to the magnetic field at all times. What is (a) the speed of the α-particle, (b) the magnitude of the magnetic force on it, and (c) the radius of its circular path?

When beryllium-7 ions (m = 11.65 × 10^-27 kg) pass through a mass spectrometer, a uniform magnetic field of 0.380 T curves their path directly to the center of the detector, as in the drawing. For the same accelerating potential difference, what magnetic field should be used to send beryllium-10 ions (m = 16.63 × 10^-27 kg) to the same location in the detector? Both types of ions are singly ionized (q = +e).

Answer 1