Question

The definition of a magic square is a matrix of distinct positive integers in which every row, column and diagonal adds up to the same number.

Given a magic square of unknown size, encoded as a nested tuple, write a python function checkMagic(square) that, given a magic square square creates a custom exception MuggleError if a given magic square is not actually magic. Otherwise, it does nothing.

python 3

Answer 1

Code

class MuggleError(Exception):

# Constructor or Initializer
def __init__(self, value):
self.value = value

# __str__ is to print() the value
def __str__(self):
return(repr(self.value))

def checkMagic(square):

try:
#calculating 1st diagonal sum
sum1 = 0
for i in range(0, len(square)) :
sum1 = sum1 + square[i][i]

# the secondary diagonal
sum2 = 0
for i in range(0, len(square)) :
sum2 = sum2 + square[i][len(square)-i-1]

if(sum1!=sum2) :
raise(MuggleError("This is not a magic square"))

# calculating each row sum and compare with sum1
for i in range(0,len(square)) :
rowSum = 0;
for j in range(0, len(square)) :
rowSum += square[i][j]
# check if every row sum is
# equal to first diagonal sum
if (rowSum != sum1) :
raise(MuggleError("This is not a magic square"))

# calculating each column sum and compare with sum1
for i in range(0, len(square)):
colSum = 0
for j in range(0, len(square)) :
colSum += square[j][i]
# check if every column sum is
# equal to first diagonal sum
if (sum1 != colSum) :
raise(MuggleError("This is not a magic square"))

except MuggleError as error:
print('A New MuggleError occured: ',error.value)

mat=(( 2, 7, 6 ),( 9, 5, 6 ),( 4, 3, 8 ))
print("matrix is")
print(mat)
print()
checkMagic(mat)

output

code snaps

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