Question

If 4.25 moles of iron (III) iodide reacts with 8.88 moles of lithium oxide, how many moles of lithium iodide is produced?

Answer 1

Balanced chemical equation is:

2 FeI3 + 3 Li2O ---> 6 LiI + Fe2O3

2 mol of FeI3 reacts with 3 mol of Li2O

for 4.25 mol of FeI3, 6.375 mol of Li2O is required

But we have 8.88 mol of Li2O

so, FeI3 is limiting reagent

we will use FeI3 in further calculation

According to balanced equation

mol of LiI formed = (6/2)* moles of FeI3

= (6/2)*4.25

= 12.75 mol

Answer: 12.8 mol