Three fair dice, each has 6 different faces, are rolled. Let B define the event that no two or no three dice show the same face. What is the probability of B
Total number of outcomes possible = 6*6*6 = 216
Number of outcomes with all different faces = 6*5*4 = 120
Hence,
P(B)
= P(No two or no three die shows the same face)
= P(All faces are different)
= 120/216
= 5/9
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