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We consider two phases of solid carbon: diamond and graphite, with S0diamond= 2.44 J/(K ∙ mol)...

We consider two phases of solid carbon: diamond and graphite, with S0diamond= 2.44 J/(K ∙ mol) and S0 graphite = 2.3 ∙ S0diamond . Which of the two carbon modifications is more stable if we establish a thermal equilibrium between them in an isolated system?

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Answer #1

As S0 for diamond is 2.44 which is greater than S0 for graphite, hence diamond will be more stable.

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