Question

A particular fruit's weights are normally distributed, with a mean of 224 grams and a standard deviation of 37 grams.

If you pick one fruit at random, what is the probability that it will weigh between 219 grams and 293 grams

Answer 1

Solution :

Given that ,

mean = = 224

standard deviation = = 37

P(219< x < 293) = P[(219-224) /37 < (x - ) / < (293-224) / 37)]

= P( -0.14< Z <1.86 )

= P(Z < 1.86) - P(Z < -0.14)

Using z table   

= 0.9686-0.4443

probability= 0.5243