What is the change in energy (in joules) if a reaction loses 399 J of heat and decreases in volume from 0.650 L to 0.225 L at a constant pressure of 4.65 atm? Please include the correct sign with your numerical result.
E = q +
w
where E = change in energy
q = heat
w = work
work done by the system (w) = -p *v
= - 4.65 atm * (0.650-0.225)L
= -1.97625 L.atm
but 1 L atm---------------------------> 101.3 joules
1.97625 L atm ----------------------> ?
=> 1.97625*101.3 = 200.2 joules
w=> 200.2 joules
q = 399 joules
if work done by the system then
E = q + w
= 399 + 200.2
= 599.2 joules
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