A random sample of 200 computer chips is obtained from one factory and 4% are found...
A random sample of 200 computer chips is obtained from one factory and 4% are found to be defective. Construct and interpret a 99% confidence interval for the percentage of all computer chips from that factory that are NOT defective.
Homework Answers
Solution:- Given that n = 200, defective = 0.04, not defective =
0.96
99% Confidence interval for Z = 2.576
99% confidence interval for the percentage of all computer chips from that factory that are NOT defective : p +/- Z*sqrt(pq/n)
= 0.96 +/- 2.576*sqrt(0.96*0.04/200)
= (0.9243 , 0.9957)
= 92.43% , 99.57%
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