Question

write a minimal driver program ( main()) test your solution

declare a classes function to model the rational number write minimal code for class declaration function including constructor set and get function and overload operator + and *

for C++

Answer 1

Given below is the code for the question. Please do rate the answer if it helped. Thank you.

Rational.h
=====
class Rational
{
   private:
       int numerator;
       int denominator;
       int gcd(int a, int b);
       void simplify();
   public:
       Rational(int num = 0, int den = 1);
       int getNumerator();
       int getDenominator();
       Rational operator +(const Rational &rhs);
       Rational operator *(const Rational &rhs);
       void display();
};
Rational.cpp
------

#include "Rational.h"
#include <iostream>
using namespace std;

void Rational::simplify(){
   int g = gcd(numerator, denominator);
   numerator /= g;
   denominator /= g;
}

Rational::Rational(int num , int den){
   numerator = num;
   denominator = den;
   if(den < 0){
       numerator = -numerator;
       denominator = -denominator;
   }
   simplify();
}

int Rational::getNumerator(){
   return numerator;
}

int Rational::getDenominator(){
   return denominator;
}
Rational Rational::operator + (const Rational &rhs){
   int n = numerator * rhs.denominator + rhs.numerator * denominator;
   int d = denominator * rhs.denominator;
   return Rational(n, d);
}

Rational Rational::operator *(const Rational &rhs){
   int n = numerator * rhs.numerator;
   int d = denominator * rhs.denominator;
   return Rational(n, d);
}

void Rational::display(){
   cout << numerator << "/" << denominator << endl;
}

int Rational::gcd(int a, int b){
   if(a < 0)
       a = -a;
  
   if(b < 0)
       b = -b;
  
   if (a == 0)
       return b;
  
   if (b == 0)
       return a;
  
   if (a == b)
       return a;

   if (a > b)
       return gcd(a-b, b);
  
   return gcd(a, b-a);
}
Test.cpp
-----
#include <iostream>
#include "Rational.h"
using namespace std;
int main(){
   Rational r1(1, 2);
   Rational r2(3, 4);
  
   cout << "r1 = ";
   r1.display();
  
   cout << "r2 = ";
   r2.display();
  
     
   cout << "r1 + r2 = ";
   Rational r3 = r1+ r2;
   r3.display();
  
   cout << "r1 * r2 = ";
   Rational r4 = r1 * r2;
   r4.display();
   return 0;
}

output
----
r1 = 1/2
r2 = 3/4
r1 + r2 = 5/4
r1 * r2 = 3/8