Question

A University of Arkansas student running for president of her sorority wanted to identify the issues are most important to the members of her sorority. To do so, she created a survey that asks various questions concerning the sorority. Thirty-seven out of 120 members completed the survey. The first question on the survey asked the members to rate the quality of food provided in the sorority house. The answers can range from 1 (very poor) to 5 (very good). The second question asked the members to state the total number of hours they individually volunteered during the semester. A 95% confidence interval showed the lower limit to be 10 hours and the upper limit to be 20 hours. What is the margin of error?

Answer 1

Solution :

Given that,

Sample mean () = (Lower limit + Upper limit ) / 2

= (10 + 20 ) / 2

= 15

Margin of error = E = Upper limit -   

= 20 - 15

Margin of error = 5