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1)Kc = 5.85 x 10^-3 at 25 C for the reaction N2O4(g)<=>PCl(g) Fifteen(15.0) grams of N2O4...

1)Kc = 5.85 x 10^-3 at 25 C for the reaction

N2O4(g)<=>PCl(g)

Fifteen(15.0) grams of N2O4 is confirmed in a 5.00L flask at 25C. calculate (A) the number of NO2 present at equilibrium and (B)the percentage of the original N2O4 that is dissociated.

(Please provide details on how to approach this problem. Thanks)

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1)Kc = 5.85 x 10^-3 at 25 C for the reaction N2O4(g)<=>PCl(g) Fifteen(15.0) grams of N2O4...
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