Initial volume V1 = 50.0 L
Initial temperature, T1 = 3 oC = (273 + 3) K = 276 K
Initial pressure, P1 = 6.89 atm
Let us say that the final volume = V2
Final temperature, T2 = 22 oC = (273 + 22) K = 295 K
Final pressure, P2 = 0.988 atm
From ideal gas law,
P1V1/T1 = P2V2/T2
or, (6.89 atm x 50.0 L)/276 K = (0.988 atm x V2)/ 295 K
or, V2 = 373 L
Hence, the new volume of the balloon = 373 L
A balloon used for underwater salvage is inflated to 50.0 L at a depth of 200...
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