Question

C++ programming language

Create a program that

1) counts from 0 to 10, but doeesn't include 10

2) counts backwards from 100 to 50 (inclusive) by 2's

Answer 1

If you have any doubts please comment below.

Cpp Code:

#include <bits/stdc++.h>

using namespace std;

// Counts the number of '2' digits in a single number

int number0f2s(int n)

{

int count = 0;

while (n > 0)

{

if (n % 10 == 2)

count++;

n = n / 10;

}

return count;

}

// Counts the number of '2' digits between 0 and 10

int numberOf2sinRange(int n)

{

// Initialize result

int count = 0 ;

// Count 2's in every number from 2 to n

for (int i = 2; i < n; i++)

count += number0f2s(i);

return count;

}

int numberOf2sinRangeBackward(int n , int m)

{

int count = 0;

for(int i=n; i>=m; i--)

count += number0f2s(i);

return count;

}

int main()

{

cout << "Counts from 0 to 10 by 2's : "<< numberOf2sinRange(10)<<endl;

cout << "Counts from 100 to 50 backwards : "<< numberOf2sinRangeBackward(100,50);

return 0;

}