Suppose you want to make an acetic acid/acetate buffer to a pH of 5.00 using 10.0...
Suppose you want to make an acetic acid/acetate buffer to a pH of 5.00 using 10.0 mL of 1.00 M acetic acid solution. How many milliliters of 1.00 M sodium acetate solution would you need to add? The pKa for acetate buffer is 4.75.
Homework Answers
no of moles of CH3COOH = molarity * volume in L
= 1*0.01 = 0.01moles
no of moles of CH3COONa = molarity * volume in L
= 1*v = v moles
PH = 5
Pka = 4.75
PH = Pka + log[CH3COONa]/[CH3COOH]
5 = 4.75 + logv/0.01
logv/0.01 = 5-4.75
logv/0.01 = 0.25
v/0.01 = 1.7783
v = 1.7783*0.01 = 0.017783
The volume of CH3COONa = v = 0.017783L
= 17.783ml >>>>>answer
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