A 640 kg sample of water at 0°C is cooled to -6°C, and freezes in the...
A 640 kg sample of water at 0°C is cooled to -6°C, and freezes in the process. How much heat is liberated? (For water Lf = 334 kJ/kg and Lv 2257 kJ/kg. The specific heat for ice is 2050 J/kg∙K.)
Group of answer choices
A)14,100 kJ
B)176,000 kJ
C)222,000 kJ
D)320,000 kJ
Homework Answers
total heat = m * lf + m c delta_T
= 640 * 334 + 640 * 2.05 * 6
= 213760 + 7872
= 221632 kJ
= approx 222000 kJ ...
so answer is option C
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